3.24.7 \(\int \frac {\sqrt {1-2 x}}{(2+3 x)^3 \sqrt {3+5 x}} \, dx\) [2307]

Optimal. Leaf size=93 \[ \frac {3 (1-2 x)^{3/2} \sqrt {3+5 x}}{14 (2+3 x)^2}+\frac {107 \sqrt {1-2 x} \sqrt {3+5 x}}{28 (2+3 x)}-\frac {1177 \tan ^{-1}\left (\frac {\sqrt {1-2 x}}{\sqrt {7} \sqrt {3+5 x}}\right )}{28 \sqrt {7}} \]

[Out]

-1177/196*arctan(1/7*(1-2*x)^(1/2)*7^(1/2)/(3+5*x)^(1/2))*7^(1/2)+3/14*(1-2*x)^(3/2)*(3+5*x)^(1/2)/(2+3*x)^2+1
07/28*(1-2*x)^(1/2)*(3+5*x)^(1/2)/(2+3*x)

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Rubi [A]
time = 0.02, antiderivative size = 93, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {98, 96, 95, 210} \begin {gather*} -\frac {1177 \text {ArcTan}\left (\frac {\sqrt {1-2 x}}{\sqrt {7} \sqrt {5 x+3}}\right )}{28 \sqrt {7}}+\frac {3 \sqrt {5 x+3} (1-2 x)^{3/2}}{14 (3 x+2)^2}+\frac {107 \sqrt {5 x+3} \sqrt {1-2 x}}{28 (3 x+2)} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[Sqrt[1 - 2*x]/((2 + 3*x)^3*Sqrt[3 + 5*x]),x]

[Out]

(3*(1 - 2*x)^(3/2)*Sqrt[3 + 5*x])/(14*(2 + 3*x)^2) + (107*Sqrt[1 - 2*x]*Sqrt[3 + 5*x])/(28*(2 + 3*x)) - (1177*
ArcTan[Sqrt[1 - 2*x]/(Sqrt[7]*Sqrt[3 + 5*x])])/(28*Sqrt[7])

Rule 95

Int[(((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_))/((e_.) + (f_.)*(x_)), x_Symbol] :> With[{q = Denomin
ator[m]}, Dist[q, Subst[Int[x^(q*(m + 1) - 1)/(b*e - a*f - (d*e - c*f)*x^q), x], x, (a + b*x)^(1/q)/(c + d*x)^
(1/q)], x]] /; FreeQ[{a, b, c, d, e, f}, x] && EqQ[m + n + 1, 0] && RationalQ[n] && LtQ[-1, m, 0] && SimplerQ[
a + b*x, c + d*x]

Rule 96

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[(a + b*
x)^(m + 1)*(c + d*x)^n*((e + f*x)^(p + 1)/((m + 1)*(b*e - a*f))), x] - Dist[n*((d*e - c*f)/((m + 1)*(b*e - a*f
))), Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1)*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, m, p}, x] && EqQ[
m + n + p + 2, 0] && GtQ[n, 0] && (SumSimplerQ[m, 1] ||  !SumSimplerQ[p, 1]) && NeQ[m, -1]

Rule 98

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[b*(a +
b*x)^(m + 1)*(c + d*x)^(n + 1)*((e + f*x)^(p + 1)/((m + 1)*(b*c - a*d)*(b*e - a*f))), x] + Dist[(a*d*f*(m + 1)
 + b*c*f*(n + 1) + b*d*e*(p + 1))/((m + 1)*(b*c - a*d)*(b*e - a*f)), Int[(a + b*x)^(m + 1)*(c + d*x)^n*(e + f*
x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, m, n, p}, x] && EqQ[Simplify[m + n + p + 3], 0] && (LtQ[m, -1] || Sum
SimplerQ[m, 1])

Rule 210

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^(-1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])
], x] /; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rubi steps

\begin {align*} \int \frac {\sqrt {1-2 x}}{(2+3 x)^3 \sqrt {3+5 x}} \, dx &=\frac {3 (1-2 x)^{3/2} \sqrt {3+5 x}}{14 (2+3 x)^2}+\frac {107}{28} \int \frac {\sqrt {1-2 x}}{(2+3 x)^2 \sqrt {3+5 x}} \, dx\\ &=\frac {3 (1-2 x)^{3/2} \sqrt {3+5 x}}{14 (2+3 x)^2}+\frac {107 \sqrt {1-2 x} \sqrt {3+5 x}}{28 (2+3 x)}+\frac {1177}{56} \int \frac {1}{\sqrt {1-2 x} (2+3 x) \sqrt {3+5 x}} \, dx\\ &=\frac {3 (1-2 x)^{3/2} \sqrt {3+5 x}}{14 (2+3 x)^2}+\frac {107 \sqrt {1-2 x} \sqrt {3+5 x}}{28 (2+3 x)}+\frac {1177}{28} \text {Subst}\left (\int \frac {1}{-7-x^2} \, dx,x,\frac {\sqrt {1-2 x}}{\sqrt {3+5 x}}\right )\\ &=\frac {3 (1-2 x)^{3/2} \sqrt {3+5 x}}{14 (2+3 x)^2}+\frac {107 \sqrt {1-2 x} \sqrt {3+5 x}}{28 (2+3 x)}-\frac {1177 \tan ^{-1}\left (\frac {\sqrt {1-2 x}}{\sqrt {7} \sqrt {3+5 x}}\right )}{28 \sqrt {7}}\\ \end {align*}

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Mathematica [C] Result contains complex when optimal does not.
time = 0.36, size = 89, normalized size = 0.96 \begin {gather*} \frac {1}{196} \left (\frac {7 \sqrt {1-2 x} \sqrt {3+5 x} (220+309 x)}{(2+3 x)^2}-1177 i \sqrt {7} \tanh ^{-1}\left (\frac {1}{7} \left (2 \sqrt {70}+3 \sqrt {70} x+3 i \sqrt {7-14 x} \sqrt {3+5 x}\right )\right )\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[Sqrt[1 - 2*x]/((2 + 3*x)^3*Sqrt[3 + 5*x]),x]

[Out]

((7*Sqrt[1 - 2*x]*Sqrt[3 + 5*x]*(220 + 309*x))/(2 + 3*x)^2 - (1177*I)*Sqrt[7]*ArcTanh[(2*Sqrt[70] + 3*Sqrt[70]
*x + (3*I)*Sqrt[7 - 14*x]*Sqrt[3 + 5*x])/7])/196

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Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(153\) vs. \(2(72)=144\).
time = 0.13, size = 154, normalized size = 1.66

method result size
risch \(-\frac {\sqrt {3+5 x}\, \left (-1+2 x \right ) \left (220+309 x \right ) \sqrt {\left (1-2 x \right ) \left (3+5 x \right )}}{28 \left (2+3 x \right )^{2} \sqrt {-\left (3+5 x \right ) \left (-1+2 x \right )}\, \sqrt {1-2 x}}+\frac {1177 \sqrt {7}\, \arctan \left (\frac {9 \left (\frac {20}{3}+\frac {37 x}{3}\right ) \sqrt {7}}{14 \sqrt {-90 \left (\frac {2}{3}+x \right )^{2}+67+111 x}}\right ) \sqrt {\left (1-2 x \right ) \left (3+5 x \right )}}{392 \sqrt {1-2 x}\, \sqrt {3+5 x}}\) \(119\)
default \(\frac {\sqrt {1-2 x}\, \sqrt {3+5 x}\, \left (10593 \sqrt {7}\, \arctan \left (\frac {\left (37 x +20\right ) \sqrt {7}}{14 \sqrt {-10 x^{2}-x +3}}\right ) x^{2}+14124 \sqrt {7}\, \arctan \left (\frac {\left (37 x +20\right ) \sqrt {7}}{14 \sqrt {-10 x^{2}-x +3}}\right ) x +4708 \sqrt {7}\, \arctan \left (\frac {\left (37 x +20\right ) \sqrt {7}}{14 \sqrt {-10 x^{2}-x +3}}\right )+4326 x \sqrt {-10 x^{2}-x +3}+3080 \sqrt {-10 x^{2}-x +3}\right )}{392 \sqrt {-10 x^{2}-x +3}\, \left (2+3 x \right )^{2}}\) \(154\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((1-2*x)^(1/2)/(2+3*x)^3/(3+5*x)^(1/2),x,method=_RETURNVERBOSE)

[Out]

1/392*(1-2*x)^(1/2)*(3+5*x)^(1/2)*(10593*7^(1/2)*arctan(1/14*(37*x+20)*7^(1/2)/(-10*x^2-x+3)^(1/2))*x^2+14124*
7^(1/2)*arctan(1/14*(37*x+20)*7^(1/2)/(-10*x^2-x+3)^(1/2))*x+4708*7^(1/2)*arctan(1/14*(37*x+20)*7^(1/2)/(-10*x
^2-x+3)^(1/2))+4326*x*(-10*x^2-x+3)^(1/2)+3080*(-10*x^2-x+3)^(1/2))/(-10*x^2-x+3)^(1/2)/(2+3*x)^2

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Maxima [A]
time = 0.53, size = 76, normalized size = 0.82 \begin {gather*} \frac {1177}{392} \, \sqrt {7} \arcsin \left (\frac {37 \, x}{11 \, {\left | 3 \, x + 2 \right |}} + \frac {20}{11 \, {\left | 3 \, x + 2 \right |}}\right ) + \frac {\sqrt {-10 \, x^{2} - x + 3}}{2 \, {\left (9 \, x^{2} + 12 \, x + 4\right )}} + \frac {103 \, \sqrt {-10 \, x^{2} - x + 3}}{28 \, {\left (3 \, x + 2\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(1/2)/(2+3*x)^3/(3+5*x)^(1/2),x, algorithm="maxima")

[Out]

1177/392*sqrt(7)*arcsin(37/11*x/abs(3*x + 2) + 20/11/abs(3*x + 2)) + 1/2*sqrt(-10*x^2 - x + 3)/(9*x^2 + 12*x +
 4) + 103/28*sqrt(-10*x^2 - x + 3)/(3*x + 2)

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Fricas [A]
time = 0.68, size = 86, normalized size = 0.92 \begin {gather*} -\frac {1177 \, \sqrt {7} {\left (9 \, x^{2} + 12 \, x + 4\right )} \arctan \left (\frac {\sqrt {7} {\left (37 \, x + 20\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1}}{14 \, {\left (10 \, x^{2} + x - 3\right )}}\right ) - 14 \, {\left (309 \, x + 220\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1}}{392 \, {\left (9 \, x^{2} + 12 \, x + 4\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(1/2)/(2+3*x)^3/(3+5*x)^(1/2),x, algorithm="fricas")

[Out]

-1/392*(1177*sqrt(7)*(9*x^2 + 12*x + 4)*arctan(1/14*sqrt(7)*(37*x + 20)*sqrt(5*x + 3)*sqrt(-2*x + 1)/(10*x^2 +
 x - 3)) - 14*(309*x + 220)*sqrt(5*x + 3)*sqrt(-2*x + 1))/(9*x^2 + 12*x + 4)

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\sqrt {1 - 2 x}}{\left (3 x + 2\right )^{3} \sqrt {5 x + 3}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)**(1/2)/(2+3*x)**3/(3+5*x)**(1/2),x)

[Out]

Integral(sqrt(1 - 2*x)/((3*x + 2)**3*sqrt(5*x + 3)), x)

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Giac [B] Leaf count of result is larger than twice the leaf count of optimal. 257 vs. \(2 (72) = 144\).
time = 0.93, size = 257, normalized size = 2.76 \begin {gather*} \frac {11}{3920} \, \sqrt {5} {\left (107 \, \sqrt {70} \sqrt {2} {\left (\pi + 2 \, \arctan \left (-\frac {\sqrt {70} \sqrt {5 \, x + 3} {\left (\frac {{\left (\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}\right )}^{2}}{5 \, x + 3} - 4\right )}}{140 \, {\left (\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}\right )}}\right )\right )} + \frac {280 \, \sqrt {2} {\left (173 \, {\left (\frac {\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}{\sqrt {5 \, x + 3}} - \frac {4 \, \sqrt {5 \, x + 3}}{\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}\right )}^{3} + \frac {29960 \, {\left (\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}\right )}}{\sqrt {5 \, x + 3}} - \frac {119840 \, \sqrt {5 \, x + 3}}{\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}\right )}}{{\left ({\left (\frac {\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}{\sqrt {5 \, x + 3}} - \frac {4 \, \sqrt {5 \, x + 3}}{\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}\right )}^{2} + 280\right )}^{2}}\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(1/2)/(2+3*x)^3/(3+5*x)^(1/2),x, algorithm="giac")

[Out]

11/3920*sqrt(5)*(107*sqrt(70)*sqrt(2)*(pi + 2*arctan(-1/140*sqrt(70)*sqrt(5*x + 3)*((sqrt(2)*sqrt(-10*x + 5) -
 sqrt(22))^2/(5*x + 3) - 4)/(sqrt(2)*sqrt(-10*x + 5) - sqrt(22)))) + 280*sqrt(2)*(173*((sqrt(2)*sqrt(-10*x + 5
) - sqrt(22))/sqrt(5*x + 3) - 4*sqrt(5*x + 3)/(sqrt(2)*sqrt(-10*x + 5) - sqrt(22)))^3 + 29960*(sqrt(2)*sqrt(-1
0*x + 5) - sqrt(22))/sqrt(5*x + 3) - 119840*sqrt(5*x + 3)/(sqrt(2)*sqrt(-10*x + 5) - sqrt(22)))/(((sqrt(2)*sqr
t(-10*x + 5) - sqrt(22))/sqrt(5*x + 3) - 4*sqrt(5*x + 3)/(sqrt(2)*sqrt(-10*x + 5) - sqrt(22)))^2 + 280)^2)

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Mupad [B]
time = 12.75, size = 1037, normalized size = 11.15 \begin {gather*} \frac {\frac {18323\,{\left (\sqrt {1-2\,x}-1\right )}^5}{875\,{\left (\sqrt {3}-\sqrt {5\,x+3}\right )}^5}-\frac {36646\,{\left (\sqrt {1-2\,x}-1\right )}^3}{4375\,{\left (\sqrt {3}-\sqrt {5\,x+3}\right )}^3}-\frac {2326\,\left (\sqrt {1-2\,x}-1\right )}{4375\,\left (\sqrt {3}-\sqrt {5\,x+3}\right )}+\frac {1163\,{\left (\sqrt {1-2\,x}-1\right )}^7}{140\,{\left (\sqrt {3}-\sqrt {5\,x+3}\right )}^7}+\frac {10607\,\sqrt {3}\,{\left (\sqrt {1-2\,x}-1\right )}^2}{4375\,{\left (\sqrt {3}-\sqrt {5\,x+3}\right )}^2}-\frac {3646\,\sqrt {3}\,{\left (\sqrt {1-2\,x}-1\right )}^4}{875\,{\left (\sqrt {3}-\sqrt {5\,x+3}\right )}^4}+\frac {10607\,\sqrt {3}\,{\left (\sqrt {1-2\,x}-1\right )}^6}{700\,{\left (\sqrt {3}-\sqrt {5\,x+3}\right )}^6}}{\frac {544\,{\left (\sqrt {1-2\,x}-1\right )}^2}{625\,{\left (\sqrt {3}-\sqrt {5\,x+3}\right )}^2}-\frac {1764\,{\left (\sqrt {1-2\,x}-1\right )}^4}{625\,{\left (\sqrt {3}-\sqrt {5\,x+3}\right )}^4}+\frac {136\,{\left (\sqrt {1-2\,x}-1\right )}^6}{25\,{\left (\sqrt {3}-\sqrt {5\,x+3}\right )}^6}+\frac {{\left (\sqrt {1-2\,x}-1\right )}^8}{{\left (\sqrt {3}-\sqrt {5\,x+3}\right )}^8}-\frac {96\,\sqrt {3}\,{\left (\sqrt {1-2\,x}-1\right )}^3}{625\,{\left (\sqrt {3}-\sqrt {5\,x+3}\right )}^3}+\frac {48\,\sqrt {3}\,{\left (\sqrt {1-2\,x}-1\right )}^5}{125\,{\left (\sqrt {3}-\sqrt {5\,x+3}\right )}^5}+\frac {12\,\sqrt {3}\,{\left (\sqrt {1-2\,x}-1\right )}^7}{5\,{\left (\sqrt {3}-\sqrt {5\,x+3}\right )}^7}-\frac {96\,\sqrt {3}\,\left (\sqrt {1-2\,x}-1\right )}{625\,\left (\sqrt {3}-\sqrt {5\,x+3}\right )}+\frac {16}{625}}-\frac {1177\,\sqrt {7}\,\mathrm {atan}\left (\frac {\frac {1177\,\sqrt {7}\,\left (\frac {7062\,\sqrt {3}}{875}+\frac {3531\,\left (\sqrt {1-2\,x}-1\right )}{875\,\left (\sqrt {3}-\sqrt {5\,x+3}\right )}-\frac {3531\,\sqrt {3}\,{\left (\sqrt {1-2\,x}-1\right )}^2}{175\,{\left (\sqrt {3}-\sqrt {5\,x+3}\right )}^2}-\frac {\sqrt {7}\,\left (\frac {212\,{\left (\sqrt {1-2\,x}-1\right )}^2}{25\,{\left (\sqrt {3}-\sqrt {5\,x+3}\right )}^2}+\frac {888\,\sqrt {3}\,\left (\sqrt {1-2\,x}-1\right )}{125\,\left (\sqrt {3}-\sqrt {5\,x+3}\right )}-\frac {536}{125}\right )\,1177{}\mathrm {i}}{392}\right )}{392}+\frac {1177\,\sqrt {7}\,\left (\frac {7062\,\sqrt {3}}{875}+\frac {3531\,\left (\sqrt {1-2\,x}-1\right )}{875\,\left (\sqrt {3}-\sqrt {5\,x+3}\right )}-\frac {3531\,\sqrt {3}\,{\left (\sqrt {1-2\,x}-1\right )}^2}{175\,{\left (\sqrt {3}-\sqrt {5\,x+3}\right )}^2}+\frac {\sqrt {7}\,\left (\frac {212\,{\left (\sqrt {1-2\,x}-1\right )}^2}{25\,{\left (\sqrt {3}-\sqrt {5\,x+3}\right )}^2}+\frac {888\,\sqrt {3}\,\left (\sqrt {1-2\,x}-1\right )}{125\,\left (\sqrt {3}-\sqrt {5\,x+3}\right )}-\frac {536}{125}\right )\,1177{}\mathrm {i}}{392}\right )}{392}}{\frac {1385329\,{\left (\sqrt {1-2\,x}-1\right )}^2}{9800\,{\left (\sqrt {3}-\sqrt {5\,x+3}\right )}^2}+\frac {1385329}{24500}+\frac {\sqrt {7}\,\left (\frac {7062\,\sqrt {3}}{875}+\frac {3531\,\left (\sqrt {1-2\,x}-1\right )}{875\,\left (\sqrt {3}-\sqrt {5\,x+3}\right )}-\frac {3531\,\sqrt {3}\,{\left (\sqrt {1-2\,x}-1\right )}^2}{175\,{\left (\sqrt {3}-\sqrt {5\,x+3}\right )}^2}-\frac {\sqrt {7}\,\left (\frac {212\,{\left (\sqrt {1-2\,x}-1\right )}^2}{25\,{\left (\sqrt {3}-\sqrt {5\,x+3}\right )}^2}+\frac {888\,\sqrt {3}\,\left (\sqrt {1-2\,x}-1\right )}{125\,\left (\sqrt {3}-\sqrt {5\,x+3}\right )}-\frac {536}{125}\right )\,1177{}\mathrm {i}}{392}\right )\,1177{}\mathrm {i}}{392}-\frac {\sqrt {7}\,\left (\frac {7062\,\sqrt {3}}{875}+\frac {3531\,\left (\sqrt {1-2\,x}-1\right )}{875\,\left (\sqrt {3}-\sqrt {5\,x+3}\right )}-\frac {3531\,\sqrt {3}\,{\left (\sqrt {1-2\,x}-1\right )}^2}{175\,{\left (\sqrt {3}-\sqrt {5\,x+3}\right )}^2}+\frac {\sqrt {7}\,\left (\frac {212\,{\left (\sqrt {1-2\,x}-1\right )}^2}{25\,{\left (\sqrt {3}-\sqrt {5\,x+3}\right )}^2}+\frac {888\,\sqrt {3}\,\left (\sqrt {1-2\,x}-1\right )}{125\,\left (\sqrt {3}-\sqrt {5\,x+3}\right )}-\frac {536}{125}\right )\,1177{}\mathrm {i}}{392}\right )\,1177{}\mathrm {i}}{392}}\right )}{196} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((1 - 2*x)^(1/2)/((3*x + 2)^3*(5*x + 3)^(1/2)),x)

[Out]

((18323*((1 - 2*x)^(1/2) - 1)^5)/(875*(3^(1/2) - (5*x + 3)^(1/2))^5) - (36646*((1 - 2*x)^(1/2) - 1)^3)/(4375*(
3^(1/2) - (5*x + 3)^(1/2))^3) - (2326*((1 - 2*x)^(1/2) - 1))/(4375*(3^(1/2) - (5*x + 3)^(1/2))) + (1163*((1 -
2*x)^(1/2) - 1)^7)/(140*(3^(1/2) - (5*x + 3)^(1/2))^7) + (10607*3^(1/2)*((1 - 2*x)^(1/2) - 1)^2)/(4375*(3^(1/2
) - (5*x + 3)^(1/2))^2) - (3646*3^(1/2)*((1 - 2*x)^(1/2) - 1)^4)/(875*(3^(1/2) - (5*x + 3)^(1/2))^4) + (10607*
3^(1/2)*((1 - 2*x)^(1/2) - 1)^6)/(700*(3^(1/2) - (5*x + 3)^(1/2))^6))/((544*((1 - 2*x)^(1/2) - 1)^2)/(625*(3^(
1/2) - (5*x + 3)^(1/2))^2) - (1764*((1 - 2*x)^(1/2) - 1)^4)/(625*(3^(1/2) - (5*x + 3)^(1/2))^4) + (136*((1 - 2
*x)^(1/2) - 1)^6)/(25*(3^(1/2) - (5*x + 3)^(1/2))^6) + ((1 - 2*x)^(1/2) - 1)^8/(3^(1/2) - (5*x + 3)^(1/2))^8 -
 (96*3^(1/2)*((1 - 2*x)^(1/2) - 1)^3)/(625*(3^(1/2) - (5*x + 3)^(1/2))^3) + (48*3^(1/2)*((1 - 2*x)^(1/2) - 1)^
5)/(125*(3^(1/2) - (5*x + 3)^(1/2))^5) + (12*3^(1/2)*((1 - 2*x)^(1/2) - 1)^7)/(5*(3^(1/2) - (5*x + 3)^(1/2))^7
) - (96*3^(1/2)*((1 - 2*x)^(1/2) - 1))/(625*(3^(1/2) - (5*x + 3)^(1/2))) + 16/625) - (1177*7^(1/2)*atan(((1177
*7^(1/2)*((7062*3^(1/2))/875 + (3531*((1 - 2*x)^(1/2) - 1))/(875*(3^(1/2) - (5*x + 3)^(1/2))) - (7^(1/2)*((212
*((1 - 2*x)^(1/2) - 1)^2)/(25*(3^(1/2) - (5*x + 3)^(1/2))^2) + (888*3^(1/2)*((1 - 2*x)^(1/2) - 1))/(125*(3^(1/
2) - (5*x + 3)^(1/2))) - 536/125)*1177i)/392 - (3531*3^(1/2)*((1 - 2*x)^(1/2) - 1)^2)/(175*(3^(1/2) - (5*x + 3
)^(1/2))^2)))/392 + (1177*7^(1/2)*((7062*3^(1/2))/875 + (3531*((1 - 2*x)^(1/2) - 1))/(875*(3^(1/2) - (5*x + 3)
^(1/2))) + (7^(1/2)*((212*((1 - 2*x)^(1/2) - 1)^2)/(25*(3^(1/2) - (5*x + 3)^(1/2))^2) + (888*3^(1/2)*((1 - 2*x
)^(1/2) - 1))/(125*(3^(1/2) - (5*x + 3)^(1/2))) - 536/125)*1177i)/392 - (3531*3^(1/2)*((1 - 2*x)^(1/2) - 1)^2)
/(175*(3^(1/2) - (5*x + 3)^(1/2))^2)))/392)/((7^(1/2)*((7062*3^(1/2))/875 + (3531*((1 - 2*x)^(1/2) - 1))/(875*
(3^(1/2) - (5*x + 3)^(1/2))) - (7^(1/2)*((212*((1 - 2*x)^(1/2) - 1)^2)/(25*(3^(1/2) - (5*x + 3)^(1/2))^2) + (8
88*3^(1/2)*((1 - 2*x)^(1/2) - 1))/(125*(3^(1/2) - (5*x + 3)^(1/2))) - 536/125)*1177i)/392 - (3531*3^(1/2)*((1
- 2*x)^(1/2) - 1)^2)/(175*(3^(1/2) - (5*x + 3)^(1/2))^2))*1177i)/392 - (7^(1/2)*((7062*3^(1/2))/875 + (3531*((
1 - 2*x)^(1/2) - 1))/(875*(3^(1/2) - (5*x + 3)^(1/2))) + (7^(1/2)*((212*((1 - 2*x)^(1/2) - 1)^2)/(25*(3^(1/2)
- (5*x + 3)^(1/2))^2) + (888*3^(1/2)*((1 - 2*x)^(1/2) - 1))/(125*(3^(1/2) - (5*x + 3)^(1/2))) - 536/125)*1177i
)/392 - (3531*3^(1/2)*((1 - 2*x)^(1/2) - 1)^2)/(175*(3^(1/2) - (5*x + 3)^(1/2))^2))*1177i)/392 + (1385329*((1
- 2*x)^(1/2) - 1)^2)/(9800*(3^(1/2) - (5*x + 3)^(1/2))^2) + 1385329/24500)))/196

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